Math, asked by kumarisomya001, 11 months ago

a cylindrical roller is used to level a playground the lenght of the roller is 4m and its diameter is 3m if the rollers roll iver 300 times to completely cover the playground find the area of the playground

Answers

Answered by suresh7898
12
here r=d/2=3/2,height=4m and 300 times rolled so,
300(CSA of cylinder)=300×2×3.14(Π)×1.5×4=11304 sq.m is the total area of the ground
Answered by wifilethbridge
21

The area of the playground is 11304 sq.m.

Step-by-step explanation:

Length of cylindrical roller = 4 m

Diameter of roller = 3 m

Radius of roller = 3/2 = 1.5 m

Curved surface area of roller = 2 \pi r h = 2 \times 3.14 \times 1.5 \times 4=37.68 m^2

Area covered in 1 rotation = 37.68 sq.m.

Area covered in 300 rotations = 37.68 \times 300 =11304 m^2

Hence  the area of the playground is 11304 sq.m.

#Learn more:

A cylindrical roller is used to level a rectangular playground. the lenght of the roller is 3.5m and its diameter is 2.8m. is the roller rolls over 200 times to completely cover the playground. find the area of the playground.

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