Math, asked by tanvika056, 1 year ago

A cylindrical roller of l=2.5m and diameter=3m when rolled on a road was found to cover the area of 3300msquare
.How many revolutions did it take???

Answers

Answered by SamuelKuruvilla15
1
CSA of a Cylinder = 2πrh = 2×(22/7)×(3/2)×(5/2) = (11/7)×15 = 23 .57 m²

 No.of revolutions  = Area of road ÷ CSA of a Cylinder = 3300 ÷ 23 .57
                               = 140 revolutions approx.



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Answered by 16Devesh16
0
hope it helps you.....
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