A cylindrical roller of l=2.5m and diameter=3m when rolled on a road was found to cover the area of 3300msquare
.How many revolutions did it take???
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CSA of a Cylinder = 2πrh = 2×(22/7)×(3/2)×(5/2) = (11/7)×15 = 23 .57 m²
No.of revolutions = Area of road ÷ CSA of a Cylinder = 3300 ÷ 23 .57
= 140 revolutions approx.
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No.of revolutions = Area of road ÷ CSA of a Cylinder = 3300 ÷ 23 .57
= 140 revolutions approx.
Please mark it as brainliest....
SamuelKuruvilla15:
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