A cylindrical roller of length 2.5m and 1.75m in radius when rolled on a road was found to cover an area of 5500m. How many revolution did it make
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curved surface area=2×22/7×1.75×2.5=275m^2
Area covered=5500m
no.of revolutions=5500/275=20 revolutions
Area covered=5500m
no.of revolutions=5500/275=20 revolutions
Answered by
14
First, we know that a cylinder rolls on its lateral surface. So we will take out the lateral surface area of the cylinder.
LSA= 2πrh
= 2×22/7×2.5×1.75
=27.5 m²
It covers an area of 5500m². Thus
No. of revolutions= Area covered/ Area of cylinder
No. of revolutions= 5500/27.5= 200
The cylindrical roller took 200 revolutions.
Hope it helps! Please mark it as 'Brainliest'!
LSA= 2πrh
= 2×22/7×2.5×1.75
=27.5 m²
It covers an area of 5500m². Thus
No. of revolutions= Area covered/ Area of cylinder
No. of revolutions= 5500/27.5= 200
The cylindrical roller took 200 revolutions.
Hope it helps! Please mark it as 'Brainliest'!
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