Question

A cylindrical tank 7 m in diameter, contains water to a depth of 4 m. Find the total area of the wet surface (pi = 3.14)

Answer 1

given that :-

• diameter of cylindrical tank = 7m or

r = 3.5 m

• height = depth of cylindrical tank = 4 m

To find :-

• total surface area of the wet surface .

instruction :-

use π = 3.14

Solution :-

we have to find out the total surface area of the cylindrical tank .

therefore,

total surface area of cylindrical tank = CSA of cylindrical tank + area of base of the tank .

total surface area of cylindrical tank = 2πrh +πr²

$\tt\: = \pi r(2h + r) \\ \\ \sf\: total \: area \: = 3.14 \times 3.5(2 \times 4 + 3.5) \\ \\ \tt\red \implies \:10.99 \times 11.5 \\ \\ \tt \red \implies \: 126.358 \: {m}^{2}$

hence, total surface area of cylindrical tank is 126.385 m².

know more about cylinder :-

curved surface area of cylinder = 2πrh total surface area of cylinder = 2πr(r + h)

volume of cylinder = πr²h

Answer 2

Answer:

given that :-

diameter of cylindrical tank = 7m or

r = 3.5 m

height = depth of cylindrical tank = 4 m

To find :-

total surface area of the wet surface .

instruction :-

use π = 3.14

Solution :-

we have to find out the total surface area of the cylindrical tank .

therefore,

total surface area of cylindrical tank = CSA of cylindrical tank + area of base of the tank .

total surface area of cylindrical tank = 2πrh +πr²

\begin{gathered}\tt\: = \pi r(2h + r) \\ \\ \sf\: total \: area \: = 3.14 \times 3.5(2 \times 4 + 3.5) \\ \\ \tt\red \implies \:10.99 \times 11.5 \\ \\ \tt \red \implies \: 126.358 \: {m}^{2}\end{gathered}

=πr(2h+r)

totalarea=3.14×3.5(2×4+3.5)

⟹10.99×11.5

⟹126.358m

2

hence, total surface area of cylindrical tank is 126.385 m².

know more about cylinder :-

curved surface area of cylinder = 2πrh total surface area of cylinder = 2πr(r + h)

volume of cylinder = πr²h