Question

A cylindrical tank 7cm in diameter contains water to a depth of 4m. What is the total area of wetted surface

Answer 1

hello....


▶▶surface [wet] = curved surface + bottom circle

▶▶radius of the cylinder r = 7/2

▶▶height of the cylinder h = 4

▶▶Area of wet surface = CSA of cylinder + Ar base circle = 2πrh + πr^2

⇒ πr(2h + r)

⇒22 x 7(8 + 3.5)7 x 2

⇒ 11 x 11.5

= 126.5 m^2


thank you...

Answer 2

Given : d = 7m , depth = 4 m

Wet area = CSA under water + area of base

Wet area = πdh + π(d/2)^2

= 3.14×7×4 + 3.14×(7/2)^2 cm^2

= 87.92 + 38.465 cm^2

= 126.385 cm^2

So, the total area of the wet surface

= 126.385 cm^2.

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