A cylindrical tank contains 498.96 liters of water.If it’s height is 0.9m,find the radius of the base.
Answers
we know,
1l = 0.001 m^3
volume of cylindrical tank = 498.96 l = 0.49896 m^3
Height of cylinderical tank = 0.9m
Volume = pi*r^2h
0.49896 = 22/7*r^2*0.9
r^2 = 0.1764
r = 0.42 m
Given,
The volume of the cylindrical tank = 498.96 liters
The height of the cylindrical tank = 0.9m
To Find,
The radius of the base of the cylindrical tank =?
Solution,
Let the radius of the base of the cylindrical tank be r
We know that 1 liter = 0.001 m³
The volume of the cylindrical tank = 498.96 liters
The volume of the cylindrical tank = 498.96/1000 m³
From the formula of the volume of the cylinder, we have
The volume = πr²h
498.96/1000 m³ = πr² * 0.9
πr² = 0.498.96/0.9
πr² = 0.5544
r² = 0.5544 * 7 / 22
r² = 3.88 / 22
r² = 0.176
r = √0.176
r = 0.42m
Hence, the radius of the base of the cylindrical tank is 0.42m.