A cylindrical tank full of water is emptied by a pipe at the rate of 225 liters per minute. How much time will it take to empty half the tank, if the diameter of its base is 3 m and its height is 3.5 m?(Use π=22/7)
Answers
Answer:
55 minutes
Step-by-step explanation:
Since the tank is cylindrical, the volume or capacity is given by:
Capacity of the tank = πr^2h
= 22/7 x 1.5 x 1.5 x 3.5
= 24.75 m^3
According to the question, we have to empty half the volume
1/2 of 24.75
= 12.375 m^3
The pipe empties 225 litres in one min
225 litres = 0.225 m^3
If it empties 0.225 m^3 in 1 minute, then time taken to empty 12.375 m^3 of water
= 12.375 / 0.225
= 55 minutes
Answer:
Tank is in the form of Hemisphere with
Diameter = 3m
so, r= 3/2 m
Volume of tank = 2/3 πr^3
= 2/ 3 × 22/7 × 3/2 ×3/2×3/2
= 99/14 m^3
= 99/14 × 1000 litres
= 99000/14 litres
volume of water to be emptied = 1/2 × volume of tank
= 1/2 × 99000/14 litres
= 99000/ 28 litres
Now, it is given that
tank is emptied at 25/ 7 litres per second.
Time taken to empty25/7 litres = 1 second
Time taken to empty 1 litre = 1×7/25 second
Time taken to empty 99000/28 litres
= 7/25 ×99000/28
= 693000/700
= 990 second
= 990/60 minute
= 16.5 minute
