Question

A cylindrical tank full of water is emptied by a pipe at the rate of 225 litres per minute. How much time will it take to empty half the tank, if the diameter of its base is 3 m and its height is 3.5 m? [Use $\pi=\frac{22}{7}$]

Answer 1

Answer:

Time taken by the pipe to empty the half tank is 55 minutes.

Step-by-step explanation:

Given :  

Diameter of cylindrical tank = 3 m

Radius of cylindrical tank ,r = 3/2 m  

Height of cylindrical tank, h = 3.5 m

Volume of cylindrical tank = πr²h  

= 22/7 × (3/2)² × 3.5  

= 22/7 × 9/4 × 3.5 = (11 × 9 × 0.5)/2

= 49.5/2 = 24.75 m³ = 24.75 × 1000 = 24750 L  

[1 m³ = 1000 L]

Volume of cylindrical tank = 24750 L  

Volume of half cylindrical tank = ½ × 24750 L = 12375 L  

Time taken by the pipe to empty 225 litres = 1 min  

Time taken by the pipe to empty 1 litre = 1/225 min  

Time taken by the pipe to empty 12375 litres = (1/225) × 12375 min = 55 min  

Hence, Time taken by the pipe to empty the half tank is 55 minutes.

HOPE THIS ANSWER WILL HELP YOU….

Answer 2

step-by-step explanation:

Diameter of the cylindrical base =3 m

∴ Radius of cylindrical tank 3/2m

= 1.5 m

Height of the tank =3.5 m

Volume of the tank piR2h

= 24.75 m3

Now, 1 m3 = 1000 liters

24.75 m3 =1000 × 24.75 liters

= 24750 liters

Full quantity of the water when it is full = 24750 m3

Quantity of water when it is half filled liters

= 12375 liters

Time taken by it to empty 225 liters 0f water = 1 minute

∴ Time taken by it empty 12375 litersof water =   12375/225 Minutes

= 55 minutes