A cylindrical tank has a capacity 6160 m^2.Find its depth if its radius is 14m.Calculate the cost of painting its curved surface at the rate of rs.3per m^2
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let h be the depth of cylindrical tank.
Given, capacity of cylindrical tank = 6160 m^2
radius ( r ) = 14 m
capacity of cylinderical tank = volume of cylinder.
Find the depth :
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volume of cylindrical tank = 6160 m^2
πr^2h = 6160
( 22 / 7 ) × (14 )^2 × h = 6160
196h = 6160 × 7/22
h = ( 6160× 7) / (196 × 22 )
h = 10 m
depth of cylinder = 10 m
Find the CSA :
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curved surface area of cylindrical tank = 2πrh
= 2 ×(22/ 7 )×14×10 = (2×22×14 ×10 )/ 7
= 6160 ÷ 7 = 880 m^2
Find the cost :
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cost of painting 1 m^2 = Rs 3
cost of painting 880 m^2=880 × 3 = Rs2640
therefore , cost of painting its curved surface area = Rs 2640
Answer : cost = Rs 2640
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Given, capacity of cylindrical tank = 6160 m^2
radius ( r ) = 14 m
capacity of cylinderical tank = volume of cylinder.
Find the depth :
---------------------
volume of cylindrical tank = 6160 m^2
πr^2h = 6160
( 22 / 7 ) × (14 )^2 × h = 6160
196h = 6160 × 7/22
h = ( 6160× 7) / (196 × 22 )
h = 10 m
depth of cylinder = 10 m
Find the CSA :
-------------------
curved surface area of cylindrical tank = 2πrh
= 2 ×(22/ 7 )×14×10 = (2×22×14 ×10 )/ 7
= 6160 ÷ 7 = 880 m^2
Find the cost :
-------------------
cost of painting 1 m^2 = Rs 3
cost of painting 880 m^2=880 × 3 = Rs2640
therefore , cost of painting its curved surface area = Rs 2640
Answer : cost = Rs 2640
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