Question

a cylindrical tank has a capacity of 3080 cm .it its depth is 20 cm, find its diameter

Answer 1

volume = 3080 cm³
depth (d)= 20 cm³


volume =πr²d

=> r²=3080/πd

r=√3080/πd cm

diameter =2r
diameter=2√3080/πd cm


put values of π and d u can calculate thw answer

Answer 2

$\large\underline\pink{Given:-}$

• Volume of cylinder = 3080 cm²
• Cylinder of depth = 20 cm

$\large\underline\pink{To find:-}$

• Fine the diameter of the base of the cylinder ....?

$\large\underline\pink{Solutions:-}$

• Volume of cylinder = πr²h

$\: \: \: \: \: \leadsto \: \: \frac{22}{7} \: \times \: {r}^{2} \: \times \: {20} \: \: = \: \: {3080}$

$\: \: \: \: \: \leadsto \: \: {22} \: \times \: {r}^{2} \: \times \: {20} \: \: = \: \: {3080} \: \times \: {7}$

$\: \: \: \: \: \leadsto \: \: {r}^{2} \: \times \: {440} \: \: = \: \: {3080} \: \times \: {7}$

$\: \: \: \: \: \leadsto \: \: {r}^{2} \: \: = \: \: \frac{{3080} \: \times \: {7}}{440}$

$\: \: \: \: \: \leadsto \: \: {r}^{2} \: \: = \: \: \frac{{308} \: \times \: {7}}{44}$

$\: \: \: \: \: \leadsto \: \: {r}^{2} \: \: = \: \: {7} \: \times \: {7}$

$\: \: \: \: \: \leadsto \: \: {r}^{2} \: \: = \: \: {49}$

$\: \: \: \: \: \leadsto \: \: {r} \: \: = \: \: {\sqrt{49}}$

$\: \: \: \: \: \leadsto \: \: {r} \: \: = \: \: {7} \: cm.$

• Now, The diameter of the base of the cylinder is 2r.

⟹ 2 × Radius

⟹ 2 × 7

⟹ 14 cm.

• Hence, The diameter of the base of the cylinder is 14 cm

$\large\underline\pink{More \: Information:-}$

• Volume of cylinder ( Area of base × height ).

= (πr²) × h

= πr²h

• Curved surface = ( Perimeter of base ) × height.

= (2πr) × h

= 2πrh

• Total surface are = Area of circular ends + curved surface area.

= 2πr² + 2πrh

= 2πr(r + h)

• Where, r = radius of the circular base of the cylinder.
• h = height of cylinder.