Question

A cylindrical tank has a capacity of 6160 m3. Diameter of its base is 28 m. Find the curved surface area of this cylinder

Answer 1

$capacity \: of \: cylndrical \: tank \: = 6160 \: {m}^{3}$

As we know that,

volume of cylinder = πr^2h

( where r is the base radius, h is the height of cylinder)

as given that

radius of cylinder, r = 28 m

hence,

π r^2h = 6160

$\frac{22}{7} \times {(28)}^{2} h = 6160 \\ \\ \frac{22}{7} \times 28 \times 28 \times h = 6160 \\ \\ h = \frac{6160 \times 7}{22 \times 28 \times 28} \\ \\ h = 2.5 \: m$

Now, we have

r = 28 m

h = 2.5 m

Also,

CSA of cylinder = 2πrh

(putting values)

$csa \: ofcylinder \: = 2 \times \frac{22}{7} \times 28 \times 2.5$

CSA of cylinder = 440 m^2

HENCE THE CURVED SURFACE AREA OF CYLINDER WILL BE 440 SQUARE METRES.