A cylindrical tank has a capacity of 6160 m3.Find its depth, if its radius is 14 m. Also find the cost of painting its curved surface at rupees 30 per m2
Answers
Answer:
Depth of the cylindrical tank = 10m
Cost of painting it's curved surface area = Rs 26400
Step-by-step explanation:
Volume of a cylindrical tank = 6160m³
=> πr²h = 6160
=> 22/7 × 14 × 14 × h = 6160
=> 44 × 14 × h = 6160
=> 616h = 6160
=> h = 6160 ÷ 616
=> h = 10m
Therefore depth of the tank = 10m
Curved surface area of the Tank
= 2πrh
= 2 × 22/7 × 14 × 10
= 88 × 10
= 880m²
Cost of Painting it's curved surface area
= 880m² × 30
= Rs 26400
Answer:
volume of any cylinder = πr²h, where π (pi) = 22/7, r is the radius of the cylinder and h is the height/depth of the cylinder. Now, cost of painting 1 m² = 30 Rs. = 26400 Rs. Therefore, cost of painting the C.S.A of the cylindrical tank = 26,400 Rs.
Step-by-step explanation:
26400 Rs. Therefore, cost of painting the C.S.A of the cylindrical tank = 26,400 Rs.