a cylindrical tank of 1metre radius rests on a platform 5m high.intially the tank is filled with water to a height of 5m.a plug area 10to the power of-4 m square is removed from an orifice on the side of a tank at the bottom.what is initial speed with which water strikes ground
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Answer:
Explanation:
so we can say that water fall with a velocity when it touches the ground now when the water leaves the orifice it will have a velocity (2gh)^1/2
so 2*5*10^1/2
which is 10
now apply laws of motion
v^2=U^2 + 2gs
so v^2= 100+ 2*10*5
so 200^1/2
is 14.14m/s
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