a cylindrical tank of diameter 2.1 m and height is 2.8m is being fed by a pipe of diameter 28cm through which water flow at the rate of 1m per second.In how many hours the tank will be filled
Answers
Answer:28minutes is the answer I hope this helps
Step-by-step explanation:
Answer: The answer is 2.62 hours
Step-by-step explanation:
Given, a cylindrical tank of diameter 2.1 m and height is 2.8m is being fed by a pipe.
Then,the height of the tank = 2.8 m
and the radius of the tank = 2.1/2 m
= 1.05 m
We know, Volume of a Cylinder, V = πr²h unit³ [Where ‘h’ is the height and ‘r’ is the radius.]
The, the volume of the cylindrical tank = π×r²×h m³
= π × (1.05)² × 2.8 m³
= 3.087π m³
Now, the diameter of the pipe is 28 cm and the water flow rate is 1 m per second.
Then, the height of the pipe(h) = 1 m
the radius of the pipe(r) = 28/2 cm
= 14 cm
= 0.14 m
Then, water flow through the pipe in 1 second = the volume of the pipe
= π×r²×h m³
= π × (0.14)² × 1 m³
= 0.0196π m³
∴The time that takes to fill the tank = 3.087π/0.0196π seconds
= 1575/10 seconds
= 1575/(10×60) hours
= 2.62 hours