A cylindrical tank of height 3 units and diameter 2 units, resting on its base, is partially filled with water up to a height h units. Thereafter it is turned horizontal and placed on a level ground with its lateral surface in contact with the ground. In this position, the maximum depth of water is units. Then h is
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Answer:
H = 0.75 units
Step-by-step explanation:
Volume of cylinder = πR^2H
R = 1 , H=3
volume of cylinder = π× 1^2 × 3
= 3π
volume of water = πr^2h
r =1
volume of water = πh
now,
when this container turned horizontal it fills at depth 1/2 units which is half of the radius
it means it fills 1/4 of total volume of cylinder
therefore , 3π /4 = πh
h = 3 /4 = 0.75 units
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