Math, asked by marinatte01, 5 months ago

 A cylindrical tank, of radius 0.35 m and height 0.70 m, is filled with water. How many cubic meters of water, to the nearest hundredth, is contained in the tank? ​

Answers

Answered by bhagyashreechowdhury
1

0.27 cubic meters of water, to the nearest hundredth, is contained in the tank.

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Let's understand a few concepts:

To calculate the cubic meters of water we will calculate here the capacity of the tank and to do that we will use the following formula of the volume of the cylinder:

\boxed{\bold{Volume\:of\:cylinder = \pi r^2 h}}

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Let's solve the given problem:

The radius of the cylindrical tank (r) = 0.35 m

The height of the cylindrical tank (h) = 0.70 m

Therefore,

The cubic meters of water that the tank can hold is,

= Capacity of the cylindrical tank

= Volume of a cylinder

= \pi r^2 h

= \frac{22}{7} \times (0.35)^2\times 0.70

= 22 \times (0.35)^2\times 0.1

= 0.2695 \:m^3

rounding it off to the nearest hundredth

= \bold{0.27\:m^3}

Thus, 0.27 m³ of water, to the nearest hundredth, is contained in the tank.

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