Question

A cylindrical tank of radius 3.5 m is filled with water through a cylindrical pipe of cross-section 38cm². If the speed of the flow of water is 0.5 cm/sec, find the height of water filled in the tank in 1 hour.​

Answer 1

now if the speed of the water is 0.5 cm per second then amount of water that will flow into the tank will be equal to 38 into 0.5 =19 cm³

Reason ( Volume = Area ×Height)

therefore in 1 hour total volume field will be equal to 1 hour × 19 cm². .......... ( 1)

now we know 1m³ =10⁶cm³

therefore 10⁶ cm³ =1m³

19cm³=19/10⁶m³..........(2)

also 1 hour is equal to 3600 seconds.

this implies that from 1

total volume filled in one hour will be equal to 19/10⁶×3600 =0.0684 m³

now volume of cylinder is equal to pi r squared ×height =3.5×3.5×22/7×H=0.0684

on solving the equation will get 0.0017

Hope it helps