Question

A cylindrical tub of radius 12 cm contains water to a depth of 20 cm

Answer 1

Answer:

Solution:-

Radius of the cylinder = 12 cm

Height of the cylinder = 6.75 cm

Let 'r' be the radius of the spherical iron ball.

Volume of the cylinder = volume of the spherical iron ball

πr²h = 4/3πr³

22/7*12*12*6.75 = 4/3*22/7*r³

3 × 12 × 12 × 6.75 = 4r³

2916 = 4r³

r³ = 2916/4

r³ = 729

r = 9 cm

So, the radius of the spherical iron ball is 9 cm.

Answer

Answer 2

$\huge | \fbox\pink{Answer}|$

$\sf{Since \: rise \: in \: water \: level \: is \: solely \: caused \: by \: ball</p><p></p><p></p><p>}$

$\sf{π×(12² )×h= \frac{4}{3} π×(9³)}$

$\sf \pink{h = 6.75 cm}$