Question

A cylindrical tub of radius=12 cm contains water to a depth of 20cm .A spherical ball of radius =9 cm is dropped in the tub and the level of water is raised by ' h ' cm.What is the value of ' h '?

Answer 1

Answer:

The Level of water raised in the cylindrical tube is 6.75 cm.

Step-by-step explanation:

Given :  

Radius of a cylindrical tube (R) =12 cm

Radius of the spherical ball , r =  9 cm.

Let Level of water raised in the cylindrical tube be h cm .

Volume of water raised in the cylindrical tube is equal to the volume of spherical ball.

Volume of water raised in the cylindrical tube = Volume of spherical ball

πR²h = 4/3πr³

R²h = 4/3r³

12² × h = 4/3 ×  9³

12 × 12 × h = 4/3 × 729  

12 × 12 × h = 4 × 243

h = (4 × 243)/ 12 × 12

h = 243/ (3 × 12)

h = 81/12 = 6.75 cm

Hence, The Level of water raised in the cylindrical tube is 6.75 cm.

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