A cylindrical tub of radius 12 cm contains water to a depth of 20 cm. A spherical iron ball is dropped into the tub and thus the level of water is raised by 13.75 cm . What is the radius of the ball?
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So, the radius of the spherical iron ball is 9 cm.
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Radius of cylinder =12 cm
Height of cylinder =6.75 cm
Let r be the radius of spherical Iron ball
Volume of cylinder = Volume of spherical ball
722×12×12×6.75=34×722×r3
2916=4r3
r3=729
r=9
Volume of cylinder =πr2h
Volume of spherical ball =34πrh
=3
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