A cylindrical tub of radius 12 cm contains water to a depth of 20 cm. A spherical from ball of radius 9 cm is dropped into the tub and thus the level of water is raised by h cm. What is the value of h?
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Answer:
The Level of water raised in the cylindrical tube is 6.75 cm.
Step-by-step explanation:
Given :
Radius of a cylindrical tube (R) =12 cm
Radius of the spherical ball , r = 9 cm.
Let Level of water raised in the cylindrical tube be h cm .
Volume of water raised in the cylindrical tube is equal to the volume of spherical ball.
Volume of water raised in the cylindrical tube = Volume of spherical ball
πR²h = 4/3πr³
R²h = 4/3r³
12² × h = 4/3 × 9³
12 × 12 × h = 4/3 × 729
12 × 12 × h = 4 × 243
h = (4 × 243)/ 12 × 12
h = 243/ (3 × 12)
h = 81/12 = 6.75 cm
Hence, The Level of water raised in the cylindrical tube is 6.75 cm.
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