Question

A cylindrical tub of radius 16 cm contains water to a depth of 35 cm . A solid metallic sphere is dropped into the tub and thus level of water is raised by 9 cm. find the radius of the ball ​

Answer 1

Answer:

r=12 cm

Step-by-step explanation:

Let the radius of the cylindrical tub

R = 16 cm

Height of the water raised ( h ) = 9 cm

radius of the iron ball = r cm

We know that ,

Volume of the cylinder = πR²h

Volume of the Sphere = ( 4 / 3)πr³

 

Volume of water raised in the tank   after immersion of the iron ball  equals to volume of the iron ball.

Volume of the iron ball = volume of  the water raised in the tank

(4/3)πr³ = πR² h

r³ = ( πR² h ) / [ (4/3 )π ]

r³ =(3 R² h) / 4

r³ = ( 3 × 16 × 16 × 9 ) / 4

r³ = ( 3 × 4 × 16 × 9 )

r³ = ( 3 × 3 × 3 × 4 × 4 × 4 )

r³ = 12 × 12 × 12

r = 12 cm

Therefore ,

radius of the iron ball = r = 12 cm

Answer 2

Answer:

radius is 12 cm . please mark my answer as brainlist.