A cylindrical tub, whose diameter is 12 cm and height 15 cm is full of ice-cream. The whole
ice-cream is to be divided into 10 children in equal ice-cream cones, with conical base
surmounted by hemispherical top. If the height of conical portion is twice the diameter of
base, find the diameter of conical part of ice-cream cone.
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Answered by
22
Diameter of cylindrical tub, 12cm
Radius, R = 12/2 = 6cm
Height, H = 15cm
Volume of cylindrical = π R2H
= 22/7 x 6 x 6 x 15
For conical portion, let radius, r and diameter, d cm
Height = 2d = 4r
For hemisphere part r1 = r cm
Total volume of ice cream = vol. of cone + vol. of hemisphere
= 1/3 π r2h + 2/3 π r13
= 1/3 π r2 (h+2r) (because r1=r)
= 1/3 x 22/7 x r2 x (4r+2r)
= 44/7 x r3
Therefore, 10 x 44/7 x r3 = 22/7 x 6 x 6 x 15
r3 = 22/7 x 6 x 6 x 15 x 7/44 x 1/10
r3 = 27
r = 3 cm
d = 6 cm
Answered by
2
15 cm is full of ice-cream. The whole
ice-cream is to be divided into 10 children in equal ice-cream cones, with conical base
surmounted by hemispherical top
hi rihan kese ho yrr
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