A cylindrical tube open at both ends is made of iron sheet which is 2cm thick. If the Outer diameter is 16 cm and its length is 100 cm, find how many Cubic centimeters of iron has been used in making the tube?
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Let the external radius be R and internal radius be r .
Since tube is the form of hollow cylinder therefore : Volume of iron used in making tube = Area of the base (which is in the form of ring ) × height of tube
=> π(R²-r²)×h
=>π(R+r)(R-r) × h
=>8800cm³
Since tube is the form of hollow cylinder therefore : Volume of iron used in making tube = Area of the base (which is in the form of ring ) × height of tube
=> π(R²-r²)×h
=>π(R+r)(R-r) × h
=>8800cm³
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Answer:
8800 cm³ (or) 0.0088 m³
Step-by-step explanation:
Length of pipe = 100 cm.
Outer diameter of the pipe = 16 cm
∴ Outer radius(R) = 8 cm.
Given, Thickness of pipe = 2 cm.
∴ Inner radius(r) = 6 cm(8 - 2).
Now,
Volume of the metal = πR²h - πr²h
= π(R² - r²)h
= 22/7 * 100 * (8² - 6²)
= 22/7 * 100 * 28
= 8800 cm³
= 0.0088 m³.
Hope it helps!
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