Question

A cylindrical tube open at both ends is made of metal the internal diameter of the tube is 11.2 cm and its length is 21 cm the metal everywhere is 0.4 cm calculate the volume of metal 21 case of decimal

Answer 1

VOLUME of TUBE

πh (R+ r)xt

h=height,/ length=21cm

R = Outer radius=5.6cm

r=inner radius 5.6-0.4=5.2cm

t = thickness (R-r) = 0.4 cm

πX2l (5.6 +5.2) xO.4

22/7X2lx10.8 x 0.4=

22x3x10.8 x 0.4=285.12cm3

Answer 2

Answer:

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