A cylindrical tube , open at both ends is made of metal. the internal diameter of the tube is 10•4 cm its length is 25 cm . the thickness of the metal is 8mm everywhere.calculate the valume of the metal
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Answer:
Step-by-step explanation:
If cylinder has inner diameter is 10.4cm and thickness is 8mm=0.8cm
∴ outer diameter is 11.2cm
∴ volume with outer diameter is =πr 2
h=3.14×(11.2) 2 *25
=9847.04cm 3
and volume with diameter inner 10.4cm is
=3.14×(10.4) 2×25
=8490.56cm 3
Now volume of metal is
=9847.04−8490.56=1356.48cm 3
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