A cylindrical tube open at both ends is made up of iron sheet of 3 cm thick if the external diameter is 10 cm and thickness 1 cm and height is 8 cm find the volume of the metal used in it
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Answer:
Volume of cylinder =πr^2 hcm^ 2
Outer radius = 16/2=8 cm
Inner radius = 8−2=6 cm
Volume =π(r′2−r2)h, where r' = outer radius and r = inner radius
=π×100×(82−62)=8792cm^3
Hence, 8792cm^3 of iron has been used in making the tube.
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