Question

a cylindrical tube open at both ends is made up of metal . internal diameter of the tube is 6 cm and the length of the cube 14 cm if the thickness of the metal used is 1 cm then find the weight of the pipe in Kg if metal weighs 10 gram per centimetre cube​

Answer 1

Therefore the weight of the pipe is 3.080 kg.

Step-by-step explanation:

Given that , a cylindrical open at both ends is made up metal.

The internal diameter of the tube is = 6 cm

The  internal  radius of the tube is(r) = (6÷2) cm = 3 cm

The external radius of the tube is(R) = internal radius +thickness

                                                            = (3+ 1) cm = 4 cm  

The volume of the tube is

$= \pi h(R^2-r^2)$

$=\frac{22}{7}\times 14 (4^2-3^2)$ cm³

=308 cm³

The weight of 1 cm³ of metal is 10 gram

The weight of 308 cm³ of metal is (10×308) gram

                                                        =3080 gram

                                                        =(3080÷1000) kg

                                                        =3.080 kg

Therefore the weight of the pipe is 3.080 kg.