a cylindrical tube open at both ends.the internal diameter of the tube is 10.4 cm and its length is 25 cm.if the thickness of tube 8mm everywhere,find the total surface area of the tube.
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I don't have a calculator with me right now, so I'll just guide you through the math. you can make the calculations yourself.
inner diameter of the tube is 10.4 cm.
inner radius= 5.2 cm.
thickness 8 mm or 0.8 cm.
therefore outer radius 5.2+.8 = 6 cm.
length/height = 25 cm.
area of the lateral surface =2πrh
= 2*π*6*25 =300π.
also, there are 2 circular rings, one at the top and another at the bottom of the tube.
area of each ring = π*6^2-π*5.2^2
or,total area of the rings 2π*(36-5.2^2) .
therefore total area of the tube =300π+2π*(36-5.2^2).
inner diameter of the tube is 10.4 cm.
inner radius= 5.2 cm.
thickness 8 mm or 0.8 cm.
therefore outer radius 5.2+.8 = 6 cm.
length/height = 25 cm.
area of the lateral surface =2πrh
= 2*π*6*25 =300π.
also, there are 2 circular rings, one at the top and another at the bottom of the tube.
area of each ring = π*6^2-π*5.2^2
or,total area of the rings 2π*(36-5.2^2) .
therefore total area of the tube =300π+2π*(36-5.2^2).
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