Question

a cylindrical
tube open at the both and is made of metal, that the inter internal diameter of the tube is 10.4 cm and its length is 25 CM the thickness of the metal is 8 mm everywhere calculate the volume of the metal in the cylinder

Answer 1

Cross sectional area of the tube = π [ ( 5.2 + 0.8 )² - 5.2² ] cm²
=> π [ 36 - 5.2² ] = 28.148 cm²
Length of the tube = 25 cm.
Hence volume of the metal = 28.148 cm² x 25 cm.
=> Volume = 703.716 cm³ = 704 cm³ ( Approximately ) ............. Answer Answer