A cylindrical tube opens at both ends is made of metal the internal diameter of the tube is 10.4 cm and length is 25cm the thickness of the metal is 8mm everywhere calculate the volume of the metal
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volume of metal used = outer volume - inner volume
=π*(r1)^2*h- π*(r2)^2*h
= πh(r1^2-r2^2)
=3.14*25*(5.6^2- 5.2^2)
=3.14*25*2.2
=172.85cm^3
=π*(r1)^2*h- π*(r2)^2*h
= πh(r1^2-r2^2)
=3.14*25*(5.6^2- 5.2^2)
=3.14*25*2.2
=172.85cm^3
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