Question

A cylindrical vessel can hold 154 g of water. If the radius of its base is3.5 cm, and 1 cm³ of water weighs 1g find the depth of water.

Answer 1

Answer:

Since 1 cm3 of water weighs 1 g.  

∴ Volume of cyclinder vessel = 154 cm3  

πr2h = 154

h = 154 × 7 / 22 × 3.5 × 3.5  

h ;= 4 cm

Hence, the depth of water is 4 cm

Answer 2

Given - Radius of base and capacity

Find - Depth of water

Solution - The depth of water is 4 centimetres.

The volume of the vessel is given by the formula = πr²d. In the formula, r is radius and d is depth.

As per the given information, 1 gram is 1 cm³, so, the volume of the vessel is 154 cm³.

Now, finding the depth.

154 = π*3.5²*d

depth = 154/(π*3.5²)

depth = 154/38.5

Depth = 4 cm

Thus, the depth of water is 4 centimetres.