Question

.
A cylindrical vessel filled with water has internal diameter 7.8 cm and height 28cm.
Its entire water is put in a rectangular tub whose base is a square of side 26cm find the height of water in the tub​.​

Answer 1

see the attachment....

Answer 2

The height of water in tub is 1.98 cm.

Step-by-step explanation:

Consider the provided information.

A cylindrical vessel filled with water has internal diameter 7.8 cm and height 28cm.

The volume of cylindrical vessel represents the amount of water it can store.

First find the volume of cylindrical vessel as shown:

$V=\pi r^2h$

It is given that diameter 7.8 cm and height 28cm.

Therefore, $r=\frac{7.8}{2}= 3.9$

Substitute the respective values in the above formula.

$V=\frac{22}{7} (3.9)^2(28)$

$V=(22)(15.21)(4)$

$V=1338.48$

Now the entire water is put in a rectangular tub whose base is a square side.

The base is square side means length = breadth

Volume of tube is: $V=l\times l\times h$

Substitute V = 1338.48 and l=26 in above formula.

$1338.48=26\times 26\times h$

$h=\frac{1338.48}{676}$

$h=1.98$

Hence, the height of water in tub is 1.98 cm.

#Learn more

https://brainly.in/question/12191397

he radius Of the base of a cylindrical vessel is 14 CM if it's height is 10 CM find the volume of this cylindrical​