A cylindrical vessel filled with water is released on an
inclined surface of angle /theta as shown in the figure. The
friction coefficient of surface with vessel is u (< tan /theta).
Then the constant angle made by the surface of water
with the incline will be
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Answer:
tan-1μ
Explanation:
Force acting on the particle on the surface of water with respect to vessel
mgsinθ and μmgcosθ are pseudo force
mgsinθ=μmgcosθ [Since no net force is acting along the surface]
tanθ=μ
θ=tan−1
Since free surface is ⊥ to the resultant force acting on it .
θ is the angle between normal to inclined surfaces and resultant force
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