Physics, asked by jyotischool1974, 9 months ago

A cylindrical vessel having its height equal to its diameter is filled with liquid and moved horizontally at acceleration equal to acceleration due to gravity. The ratio of the liquid left in the vessel to the liquid at static equilibrium condition is:
a)0.2
b)0.4
c)0.5
d)0.75
With explaination

Answers

Answered by Anonymous
8

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Answered by techtro
6

Given :

- Height of cylinder = Diameter of cylinder

- Acceleration of moving horizontally = Acceleration due to gravity

To find :

• The ratio of the liquid left in the vessel to the liquid at static equilibrium condition

Solution :

• Let height and diameter of cylinder be L and D respectively.

L = D

• From information given in question,

tan θ = g / g+g

= g / 2g

= 1/2

• Also,

tan θ = h / L = 1/2 = 0.5

• Hence, the ratio of the liquid left in the vessel to the liquid at static equilibrium condition solution is 0.5

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