Question

A cylindrical vessel is filled with equal amounts by weights of mercury and water. The total height of the two layers is 29.2 cm .The pressure of the liquid at the bottom of the vessel is???

Answer 1

A cone figure

I hope this helps

Answer 2

Hello dear,

● Answer- 40 mm Hg

● Explaination-
# Given-
Mw = Mhg
Lw + Lhg = 29.2 cm
ρhg/ρw = 13.6

# Solution-
We have
Mw = Mhg
ρw.A.Lw = ρhg.A.Lhg
ρhg / ρw = Lw / Lhg
13.6 = Lw / Lhg
Lw = 13.6 Lhg

Also, Lw + Lhg = 29.2
13.6 Lhg + Lhg = 29.2
Lhg (13.6+1) = 29.2
Lhg = 29.2 / 14.6
Lhg = 2 cm = 20 mm Hg

As Mw = Mhg
Pw = Phg
P = Pw + Phg = 2 Phg
P = 20×2 = 40 mm Hg

Therefore total pressure will be 20×2 = 40 mm Hg.

Hope this is useful...