A cylindrical vessel of diameter 12 cm contains 800π cm3 of water. A cylindrical glass piece of diameter 8.0 cm and height 8.0 cm is placed in the vessel. If the bottom of the vessel under the glass piece is seen by the paraxial rays (see figure 18-E6), locate its image. The index of refraction of glass is 1.50 and that of water is 1.33.
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Given :
r= 6cm
r1=4cm
h1=8cm
let h be the height of wtaer column
The volume of the cylindrical water column after the glass piece is
π r² h= 800π + π r1² h1
r² h= 800 + r1² h1
6² h = 800+ 4² x 8
h= 800+ 128/36
= 929/36
= 25.7 cm
There are two shifts due to glass slab and water
Δt1=[1-(1/μ)xt
=[1- (1/3/2)]x 8=2.26cm
Δt1=[1-(1/μ)xt
=[1-(1/4/3)(25.7-8)
= 4.44cm
∴Total shift = 2.66+4.47= 7.1cm
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Given r = 6 cm, r1 = 4 cm, h1 = 8 cm
Let, h = final height of water column.
The volume of the cylindrical water column after the glass piece is put will be,
Let, h = final height of water column.
The volume of the cylindrical water column after the glass piece is put will be,
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