Question

A Cylindrical vessel of radius 5cm is filled with water upto a height of 20cm. The cylinder is open to atmosphere at the top. A small aperture of radius 2mm is made on the side of the cylinderat a height of 5cm from the bottomof the vessel. For approximately how long will water tank leak out of the aperture?


A) 2 minutes and 48 seconds
B) 1 minute and 48 seconds
C) 2 minutes and 11 seconds
D) 1 minute and 11 seconds​

Answer 1

Answer:

B.for 1minute and 48 second

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Explanation:

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Answer 2

Conclusion

Time

Time can be defined as the dimension through which the evolution of any system occurs. It is quantifiable in seconds, minutes, hours, days, weeks, months, and years.

Main content

The time required to leak out if the aperture will be = 1 min and 48 seconds.

The the correct answer is (B)

It is given:

$Height = 20cm -5cm=15\times10x^{-2}m\\ Area_{1} = A = 25 \pi \times 10^{-2} m\\Area_2 = A = 2 \pi \times 10^{-2}m\\Considering, g = 10 m/s^2\\So,. We know that\\time, t=\frac{A}{A0} \sqrt{ \frac{2H}{g} }$

Putting all the valve, we get :

$t=\frac{25 \times10^{-2}}{2\times10^{-2}} \sqrt{\frac{2\times15\times10^{-2}}{10} }\\or, t=108 sec\\or, t = 1,minute and 48 seconds$

So therefore, the time required to leak out if the aperture will be = 1 min and 48 seconds

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