A cylindrical vessel open at the top has a base diameter 56cm if the total cost of painting the outer curved surface of the vessel is 352 rupee at the rate rupee 0.2 per 100cm square then the height of the vessel is
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Find the area of the curved surface:
Rs 0.20 = 100 cm²
Rs 1 = 100 ÷ 0.2 = 500 cm²
Rs 352 = 500 x 352 = 176000 cm²
Find the radius:
Radius = Diameter ÷ 2
Radius = 56 ÷ 2 = 28 cm
Find the height:
Curved surface area = 2πrh
Given that area = 176000 cm² and the radius = 28 cm
2π(28)h = 176000
56πh = 176000
h = 176000 ÷ 56π
h = 1000 cm or 10m
Answer: The height is 10 m
naman861:
Thank you
Answered by
3
Thank you so much for asking this question, here is your answer:
Curved Surface: = 2πrh
352 = 2 x 227 x 28 x h
352 = 44 x 4 x h
352 = 156 x h
352/156 = h
when we solve the above equation we will get this:
86/39 x 0.2 / 10 x 100
44.10 is the final answer for this question.
If there is any confusion please leave a comment below.
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