Question

A cylindrical vessel open at the top has a base of radius 10.5cm and height 14cm. Find the cost of painting the inner part of vessel at the rate of ₹10 per hundred sq. cm.​

Answer 1

Answer:

Step-by-step explanation:

r = 10.5 cm

h = 14 cm

inner area = inner curved surface area  + base area

              = 2πrh + πr²

              = 2×(22/7)×14×10.5 + (22/7)×10.5²

              = 1270.5 cm²

rate = ₹10 per cm²

cost = 1270.5×10 = ₹12705

Answer 2

Answer:

$cost = rupees \: 1270.5 \times 10 \\ = 12705$