A cylindrical vessel open at the top has a base of radius 10.5 cm and height 14 cm find the cost of painting the inner part of the vessel at the rate of 10 ₹ per hundred sq. cm
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curved surface area + base area
=2πrh +πr^2
=(2×22/7×10.5) +(22/7×10.5)
=(924cm^2+33cm^2)
=957cm^2.
rate of painting=₹10/sq cm^2.
so,total cost=₹957×10
=₹9570.
=2πrh +πr^2
=(2×22/7×10.5) +(22/7×10.5)
=(924cm^2+33cm^2)
=957cm^2.
rate of painting=₹10/sq cm^2.
so,total cost=₹957×10
=₹9570.
shams8:
answer is 127.75 ₹
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