a cylindrical vessel open at the top has a base of radius 10.5cm and height 14cm. find the cost of painting the inner part ofthe vessel at the rate of rupees10 per hundred sq.cm.
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Radius of the cylinder = 10.5cm
height of the cylinder = 14cm
CSA of the cylinder = 2πrh
= 2× 22/7 × 10.5 × 14 = 924cm²
area of base of the cylinder = πr²
= 22/7 × 10.5× 10.5 = 346.5cm²
Total area to be painted = CSA + area of base= 924+ 346.5= 1270.5cm²
Cost of painting of 1 cm² = 10
Therefore,
Cost of painting of 1270.5 cm² = 1270.5 × 10= Rs.12705..
height of the cylinder = 14cm
CSA of the cylinder = 2πrh
= 2× 22/7 × 10.5 × 14 = 924cm²
area of base of the cylinder = πr²
= 22/7 × 10.5× 10.5 = 346.5cm²
Total area to be painted = CSA + area of base= 924+ 346.5= 1270.5cm²
Cost of painting of 1 cm² = 10
Therefore,
Cost of painting of 1270.5 cm² = 1270.5 × 10= Rs.12705..
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