A cylindrical vessel open at the top has a base of radius 10.5 cm and height 14 cm . Find the cost of painting the inner part of the vessel at the rate of rupees 10 per hundred sq . cm .
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r=10.5 cm
h=14 cm
inner area=base area+inner curved area
base area=πr²=22/7*10.5²=346.5 cm²
Inner curved area=2πrh=2*22/7*10.5*14=924 cm²
then inner curved area=346.5+924=1270.5 cm²
10 ruppee per cm²\
so total cost=10*1270.5=12705 ruppee
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1
Answer:
Step-by-step explanation:
Total surface area of the cylinder
= 22/7 ( value of pie) × radius ( hieght + radius)
= 22/7 ×10 . 5 (14 +10 . 5)
808 . 5 sq. cm
Cost of painting = 808.5 × 0.10
= Rupees 80.85
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