a cylindrical vessel open at the top has a base radius of 4.9 cm and height of 35 cm. find the cost of painting its surface at 5rupees pet hundred square cm
Answers
Answer:
The cost of painting the surface of the vessel is Rs. 5762.0572
Step-by-step explanation:
Given the radius of the cylinder = 4.9 cm
The height of the cylinder = 35 cm
Total area that needs to be painted = CSA + Area of the base
We know that CSA = Curved Surface Area = 2πrh
and Area of the base = πr²
where r = radius of the cylinder
h = height of the cylinder
Therefore, Total area that needs to be painted = 2πrh + πr²
= πr(2h + r)
On substituting the values,
πr(2h + r) = π*4.9(2*35 + 4.9)
= π*4.9(70 + 4.9)
= π*4.9(74.9)
= 3.14*367.01
= 1152.4114 cm²
We know that Cost = Rate * Area
= 5 * 1152.4114
= 5 * 1152.4114
= 5762.0572
Therefore, the cost of painting the surface of the vessel is Rs. 5762.0572