Question

A cylindrical vessel, open at the top, has a radius 10 cm and height 14 cm. Find the total surface area of the vessel. (Take
$\pi$
= 3.14)
​​

Answer 1

Answer:

Area of the cylinder includes lower curved surface , upper curved surface lateral surface including height . Given that the cylinder is open at the top . This means that the surface area of the lid should not be considered. So , only lateral surface and lower surface should be considered . Area of the cylindrical surface 2arh + ar Where r is the radius of the curved surface , h is the height between two curved surfaces as shown in the below attached figure . = Area = 2nrh + ar2 2 x 3.14 x 10 x 14 + 3.14 x 10 x 10 ( TT is 3.14 , r = 10 , h = 14 ) = 879.2 + 314 1193.2 cm2

Answer 2

Answer:

Given :

A car has an constant acceleration of 4

m/s², starting from rest it reaches the

speed of 40 m/s.

To Find:

• Distance travelled by the car.

Solution :

→ Initial Velocity (u) = 0 m/s

→Final Velocity (v)=40 m/s

→Acceleration (a)= 4 m/s²

For Time:

Using 1st Equation :

v=u+ at

Putting Values:

40=0+4 t

40 =4 t

$\frac{40}{4} = t$

→→10 sec = t

Now,

For Distance Travelled :

Using 2nd Equation :

$s = ut + \frac{1}{2} {at}^{2}$

Putting Values:

$0 \times 10 + \frac{1}{2} \times 4 \times ({10}) ^{2}$

$0 \times 10 \times \frac{1}{2} \times 4 \times 100$

0 + 2 x 100

200 m

So, The Distance Travelled by the car is

200 m.