Question

a cylindrical vessel opened at the top has a base of diameter is 42cm and height is 50cm find the cost of tin plating its inner part at the rate of rupee 12 per 100 cm square​

Answer 1

Answer:

Anuska whatsaap pr mile meri profile se no le lo Fir bat krte hai

Ok

Answer 2

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Given:

diameter of the vessel = 42cm

radius of the vessel = $\mathsf{\frac{42}{2}cm}$ = 21 cm

height of the vessel = 50 cm

let the radius and height be R and H respectively

According to the question, It is given that the top of the cylindrical vessel is opened.

So, we have to subtract the top part

Required Area = Total Surface Area - Area of the top part of the vessel

$\mathsf{\implies\: 2\pi R(R+H) - \pi R^2}$

$\mathsf{\implies\: 2 × \frac{22}{7} × 21 (21 + 50) - \frac{22}{7} × (21)^2}$

$\mathsf{\implies\: 142 × 71 - 1486}$

$\mathsf{\implies\: 10082 - 1486}$

$\mathsf{\implies\: 8586 cm^2}$

Cost of plating 100cm² = ₹12

So, cost of plating 8586cm² = ₹85.86 × 12

===> ₹1030.32