A cylindrical vessel, without lid, has to be tin-coated including both of its sides. If the radius of Its base is 1/2 m and its height is 1. 4 m, calculate the cost of tin coating at the rate of Rs. 50 per 1000 cm. (Note : Base is 1/2 m)
Answers
Answer
Given
- Base of cylindrical vessel is 1/2 m
- Height of cylindrical vessel is 1.4 m
- Rate of tin coating is Rs. 50 per 1000 sq. cm.
Find
- Cost of tin coating
Solution
1000 sq. cm = 1 sq. m
Given that cylindrical vessel, without lid, has to be tin-coated i.e we need to calculate the lateral surface area of cylinderical vessel
We know that ,
Lateral surface area of cylinder
=> A = 2πrh
Where,
- A = Lateral surface area of cylinderical vessel
- r = Radius of cylinderical vessel
- h = Height of cylinderical vessel
For the given cylinderical vessel
- r = 1/2 = 0.5 m
- h = 1.4 m
Putting the above values
=> 2πrh
=> 2(22/7)(0.5)(1.4)
=> 2(22)(0.5)(0.2)
=> 1(22)(0.2)
=> 4.4 sq. m.
Cost of tin coating
Area in sq. m x Rate per sq. m
=> 4.4 x 50
=> Rs. 220
- Hence the cost of tin coating is Rs. 220
Answer
Given
Base of cylindrical vessel is 1/2 m
Height of cylindrical vessel is 1.4 m
Rate of tin coating is Rs. 50 per 1000 sq. cm.
Find
Cost of tin coating
Solution
1000 sq. cm = 1 sq. m
Given that cylindrical vessel, without lid, has to be tin-coated i.e we need to calculate the lateral surface area of cylinderical vessel
We know that ,
Lateral surface area of cylinder
=> A = 2πrh
Where,
A = Lateral surface area of cylinderical vessel
r = Radius of cylinderical vessel
h = Height of cylinderical vessel
For the given cylinderical vessel
r = 1/2 = 0.5 m
h = 1.4 m
Putting the above values
=> 2πrh
=> 2(22/7)(0.5)(1.4)
=> 2(22)(0.5)(0.2)
=> 1(22)(0.2)
=> 4.4 sq. m.
Cost of tin coating
Area in sq. m x Rate per sq. m
=> 4.4 x 50
=> Rs. 220
Hence the cost of tin coating is Rs. 220