Math, asked by shaikhsadat935, 9 months ago

A cylindrical water tank of diameter 1.4 m and 2.1 m is being fed by a pipe of diameter 3.5 cm through which water flows at the rate of 2 m/s in how much time will the be filled
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Answers

Answered by Anonymous
40

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\sf\underbrace{Given: }

A cylindrical water tank of diameter 1.4 m and height 2.1 m is being fed by a pipe of diameter 3.5 cm through which water flows at the rate of 2 metre per second. In how much time the tank will be filled?

\sf\underline\red{Solution:}

We have,

  • Diameter of cylindrical tank = 1.4 m
  • Radius of tank = d/2 = 1.4/2 = 0.7m
  • Height of tank = 2.1 m

Diameter of pipe flowing water in tank = 3.5 cm

  • Radius of pipe = d/2 = 3.5/2 cm
  • Rate of flow of water = 2 m/s

Time taken to fill the tank = volume of tank / volume of pipe × rate of flow

ㅤㅤ→\sf{= πr\:‑\:2h\: / \:(πr\:‑\:2 \:×\: 2)}

\\

ㅤㅤ\\→\sf{=\: (π \:×\: 0.7\: ×\: 0.7 \:× \:2.1)}/\sf{\:(π\: ×\: 3.5/2 × 3.5/2\: × \:2)}

\\

ㅤㅤ→\sf{=\: 1.029\: / \:6.125}

\\

ㅤㅤ→\sf{= \:0.168}

\\

ㅤㅤ→\sf{= \:1680 \:seconds}

\\

ㅤㅤ→\sf{= \:28 \:minutes.}

\\

∴ Time taken to fill the tank is 28minutes.

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\sf\underbrace{To\: know\:More: }

Some Formula of Cylinder

Curved surface Area of cylinder = 2πrh.

  • → Base Area of cylinder = πr²

  • → Both Side base Area of cylinder = 2(πr²)

  • → Total Surface Area of cylinder = curvedsurface Area + both side base Area = 2πrh + 2πr² = 2πr (h+r)..

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