A cylindrical water tank with radius of base 70 CM and height 2M is to be filled with a pipe with Internal diameter 3.5CM and speed of water in it is 3M per second. Find the time required to fill the tank
Answers
Answer:
Given diameter = 1.4 m
Radius = 1.4 / 2 = 0.7 m
Also h = 2.1 m
We know that volume of tank = π r^2 h
= 22/7 x 0.7 x 0.7 x 2.1
Now dimensions of pipe will be
Diameter = 3.5 cm
Radius = D / 2
= 3.5 / 2
= 3.5 / 200 m
Height = 2 m
Now volume of water delivered in 1 sec will be π r^2 h
= 22/7 x 3.5 / 200 x 3.5/200 x 2 m^3
When tank is filled let time be x.
Volume of tank = volume of water delivered in x sec
So 22/7 x 0.7 x 0.7 x 2.1 = 22/7 x 3.5 / 200 x 3.5/200 x 2 x x m^3
So x = 0.7 x 0.7 x 2.1 x 200 x 200 / 3.5 x 3.5 x 2
= 1680 sec
= 1680 / 60
= 28 min
So the tank will be fully filled in 28 minutes.
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