a cylindrical well 21 metre deep. its outer and inner diameters are 21 m and 14 m respectively. find the cost of the renovating the inner curved surface area and the outer curved surface area at the rate of rs 25 per metre square
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Outer diameter=21m
Then radius=1/2×21=10.5m
Inner diameter= 14m
Then radius=7m
CSA of a cylinder=2pirh
2×22/7×7×14=616m2
This is of the inner radius
CSA of outer radius=
2×22/7×10.5×21=1386m2
Cost of renovation of outer radius =
1386×25=rs 34600
Cost of renovation of inner radius=
616×25=rs 15400
Therefore the,cost of inner and outer radius =
Rs 34600 and rs 15400 respectively.
Hope it is useful for u thank u
Then radius=1/2×21=10.5m
Inner diameter= 14m
Then radius=7m
CSA of a cylinder=2pirh
2×22/7×7×14=616m2
This is of the inner radius
CSA of outer radius=
2×22/7×10.5×21=1386m2
Cost of renovation of outer radius =
1386×25=rs 34600
Cost of renovation of inner radius=
616×25=rs 15400
Therefore the,cost of inner and outer radius =
Rs 34600 and rs 15400 respectively.
Hope it is useful for u thank u
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